Friday, March 10, 2017

inorganic chemistry - Why is gold golden?


Bulk gold has a very characteristic warm yellow shine to it, whereas almost all other metals have a grey or silvery color. Where does this come from?


I have heard that this property arises from relativistic effects, and I assume that it has to do with some distinct electronic transition energies in the gold atoms. But what changes with the "introduction" of relativistic effects, that then changes the energy of the frontier orbitals in such a drastic manner?



Answer



Yes, this is a beautiful question.


As you said, in lower rows of the periodic table, there are relativistic effects for the electrons. That is, for core electrons in gold, the electrons are traveling at a significant fraction of the speed of light (e.g., ~58% for Au $\ce{1s}$ electrons). This contracts the Bohr radius of the 1s electrons by ~22%. Source: Wikipedia


This also contracts the size of other orbitals, including the $\ce{6s}$.


The absorption you see is a $\ce{5d->6s}$ transition. For the silver $\ce{4d->5s}$ transition, the absorption is in the UV region, but the contraction gives gold a blue absorption (i.e., less blue is reflected). Our eyes thus see a yellow color reflected.


There's a very readable article by Pekka Pyykkö and Jean Paul Desclaux that goes into more detail (if you subscribe to ACS Acc. Chem.Res.)


No comments:

Post a Comment

periodic trends - Comparing radii in lithium, beryllium, magnesium, aluminium and sodium ions

Apparently the of last four, $\ce{Mg^2+}$ is closest in radius to $\ce{Li+}$. Is this true, and if so, why would a whole larger shell ($\ce{...