The above compound – 2,3,7,8-tetramethylspiro[4.4]nonane – clearly exhibits both optical and geometrical isomerism. The question is, how many stereoisomers does it have in all?
As the number of possibilities are many, I couldn't really visualise the molecule's all possible stereoisomers properly. Could someone please help me count the total number of stereoisomers?
I figured that the carbon common to both rings is sp3 hybridised (tetrahedral geometry), and the two rings don't lie in the same plane.
Answer
The compound 2,3,7,8-tetramethylspiro[4.4]nonane has five potential stereogenic or pseudoasymmetric centres: the four C atoms with the methyl substituents and the spiro atom. In total there are $2^5=32$ possible configurations. However, many of these combinations are actually identical compounds.
A simple and obviously exhaustive (but also exhausting) approach is to draw all 32 configurations and name them. (This approach may also be used to check the results if someone finds a more elegant solution.) The resulting names for the 32 combinations are:
- (2R,3R,7R,8R)-2,3,7,8-tetramethylspiro[4.4]nonane (2 times)
- (2R,3R,7R,8S)-2,3,7,8-tetramethylspiro[4.4]nonane (8 times)
- (2R,3R,7S,8S)-2,3,7,8-tetramethylspiro[4.4]nonane (4 times)
- (2R,3S,5r,7R,8S)-2,3,7,8-tetramethylspiro[4.4]nonane (4 times)
- (2R,3S,5s,7R,8S)-2,3,7,8-tetramethylspiro[4.4]nonane (4 times)
- (2R,3S,7S,8S)-2,3,7,8-tetramethylspiro[4.4]nonane (8 times)
- (2S,3S,7S,8S)-2,3,7,8-tetramethylspiro[4.4]nonane (2 times)
Therefore, there are seven different combinations.
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