For the Electrolysis of Copper Chloride:
Cathode: CuX2++2eX−−⇀↽−Cu
Anode: 2Cl−⇀↽−ClX2+2eX−
I am confused about the reaction taking place at the anode. Wouldn't HX2O rather undergo oxidation since it has an increased reducing ability? eg. It is above 2ClX− on the Table of Standard Reduction Potentials.
Am I missing something? Or do all halogens discharge more readily than water?
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