What is the method to be followed to prepare $\ce{Sn(NO3)2}$?
I tried to prepare $\ce{Sn(NO3)2}$ from reaction below:
$$\ce{SnCl2 + 2HNO3-> Sn(NO3)2 + 2HCl}$$
But $\ce{SnCl2}$ is not soluble. We are getting a turbid solution.
Apparently the of last four, $\ce{Mg^2+}$ is closest in radius to $\ce{Li+}$. Is this true, and if so, why would a whole larger shell ($\ce{...
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