When naming branched alkenes/alkynes, the numbers of the carbons where the branches and multiple bonds are located are supposed to be the lowest possible. Do the branches take precedence over the multiple bonds, as for example, 2-methyl-3-pentyne? If the counting of the carbons for this molecule is flipped so that the triple bond is lower in number, it would be 3-methyl-2-pentyne. Is the first way correct?
Answer
Unsaturated bonds take precedence over "branches". Consider these bonds as functional groups and name the compound, it will make you number carbons correctly.
Also the compound you mentioned above can't possibly exist as it has 5 bonds on $\ce{C_3}$.
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