Wednesday, October 25, 2017

signal detection - I and Q Channels


My understanding of I and Q channels is as follows (please correct me if I am wrong):



  • I = In-phase, or real component

  • Q = Quadrature (90° shift of real component)



Where do these two channels come from in the first place? Is one the electric field and the other the magnetic field of a EM wave? I was under the impression that these channels are only present in digital waveforms; if this is true, and if so, why?


How can this be used to find the vector of on incoming signal, and would the signal modulation make a difference (assuming you can invoke the proper filtering necessary)?



Answer



The two channels exist only inside a transmitter or a receiver; the channels are physically combined in a single signal (or channel) in the physical medium (wire, coax cable, free space, etc). At the transmitter, two signals sI(t) and sQ(t) (called the I (or inphase) signal and Q (or quadrature) signal respectively) are combined into a single signal s(t) that is transmitted over the physical medium in a frequency band centered at ωc radians per second. Note that s(t)=sI(t)cos(ωct)sQ(t)sin(ωct)

The receiver separates out the two signals sI(t) and sQ(t) from this by multiplying s(t) by 2cos(ωct) and 2sin(ωct) respectively, and low-pass filtering the two products. That is, sI(t)=result of low-pass filtering of 2s(t)cos(ωct)sQ(t)=result of low-pass filtering of 2s(t)sin(ωct)
Note that 2s(t)cos(ωct)=2sI(t)cos2(ωct)2sQ(t)sin(ωct)cos(ωct)=sI(t)+[sI(t)cos(2ωct)sQ(t)sin(2ωct)]2s(t)sin(ωct)=2sI(t)cos(ωct)sin(ωct)+2sQ(t)sin2(ωct)=sQ(t)+[sQ(t)cos(2ωct)sI(t)sin(2ωct)]
where the quantities in square brackets are double-frequency terms that are eliminated by the low-pass filtering.


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